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N2(g)+O2(g )---------->2NOg
IÂ Â Â Â Â Â Â Â x
       2 0
C -1.6 Â Â -1.6 Â Â 1.6
E Â Â x-1.6 0.4 1.6
  Kc = [NO]2/[N2][O2]
0.469 = (1.6)2/(x-1.6)(0.4)
0.469(x-1.6)(0.4) = 2.56
        Â
0.1876x-0.30016Â Â Â = 2.56
       Â
0.1876x               Â
= 2.56+0.30016
      Â
0.1876x               Â
= 2.86016
                Â
x                Â
=2.86016/0.1876Â Â Â = 15.246 moles
[N2]Â Â = x-1.6 = 15.246-1.6 = 13.646moles
molarity of N2 = 13.646/0.25Â Â =54. 584M
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