Total charge (q) of the molecular ion = -10e
                                                       =
-10(1.6*10-19C)
                                                       =
-1.6*10-18C
Now the electric field strength (E) in between the cell
membraneis
                      E
= V / d
                          =
(70mV) / (5.0nm)
                          =
(70.0*10-3V) / (5.0*10-9m)
                          =
14.0*106V/m
Now the electric force acting on the molecule is
              F
= Eq
                 =
(14.0*106V/m)(1.6*10-18C)
                 =
22.4*10-12N
The direction of the electric force is in opposite direction to
thedirection of the electric field
