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The distinctive odor of vinegar is due to acetic acid, HC2H3O2. Acetic acid reacts with sodium...

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Chemistry

The distinctive odor of vinegar is due to acetic acid, HC2H3O2.Acetic acid reacts with sodium hydroxide in the following fashion:HC2H3O2(aq) + NaOH(aq)-> H2O(l) + NaC2H3O2(aq). If 2.52 mL ofvinegar requires 34.9 mL of 0.1031 M (molarity) NaOH to reach theequivalence point in a titration, how many grams of acetic acid arein a 1.00 qt sample of this vinegar? (1 L = 1.0567 qt)

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4.3 Ratings (635 Votes)

HC2H3O2(aq) + NaOH(aq)-> H2O(l) + NaC2H3O2

no of moles of NaOH = molarity of NaOH * volume in L

                             = 0.1031*0.0349 = 0.003598 moles

From balanced equation 1 mole of CH3COOH react with 1 mole of NaOH

no of moles of NaOH = no of moles of CH3COOH

no of moles of CH3COOH = 0.003598 moles

2.52 ml vinegar contains 0.003598 moles

mass of CH3COOH = no of moles * G.M.Wt

                           = 0.003598*60 = 0.2159 gm

                           = 0.2159*1000/2.52 = 85.67g/L

1 US quart = 0.95L

                             = 85.67*0.95 =81.38gm acetic acid ina 1qt sample of vinegar
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