The drawing shows an exaggerated view of a rifle that has been‘sighted in' for a 91.4-meter target. If the muzzle speed of thebullet is v0 = 475 m/s, there are the twopossible angles θ1 and θ2between the rifle barrel and the horizontal such that the bulletwill hit the target. One of these angles is so large that it isnever used in target shooting. Give your answers as(a) the smaller angle and (b) thelarger angle. (Hint: The following trigonometric identity maybe useful: 2 sinθ cosθ = sin2θ.)
I have been able to get to sin2θ = (9.8m/s^2) (91.4m) /(475 m/s)^2 but i am not sure what to do from here and keep gettingthe answer wrong.
