The equilibrium constant in terms of pressures for the reduction of
tungsten(IV) oxide to tungsten at
25...
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Chemistry
The equilibrium constant in terms of pressures for the reduction oftungsten(IV) oxide to tungsten at25 °C is Kp = 3.82×10-4,corresponding to the reaction
WO2(s) +2CO(g) = (doublearrow) W(s) +2CO2(g)
If the total pressure of an equilibrium system at 25 °C is2.67 atm, calculate the partial pressures ofCO(g) andCO2(g).
PCO =Â Â atm
PCO2 =Â Â atm
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3.9 Ratings (450 Votes)
Few things we have to remember in this type of problems Thetotal pressure given in the problem is the sum of
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