The equilibrium constant, K, for the following reaction is
1.20×10-2 at 500 K. PCl5(g) PCl3(g) +...
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Chemistry
The equilibrium constant, K, for the following reaction is1.20×10-2 at 500 K. PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixtureof the three gases in a 1.00 L flask at 500 K contains 0.218 MPCl5, 5.11×10-2 M PCl3 and 5.11×10-2 M Cl2. What will be theconcentrations of the three gases once equilibrium has beenreestablished, if 3.92×10-2 mol of PCl3(g) is added to the flask?[PCl5] = M
[PCl3] = M
[Cl2] = M
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3.6 Ratings (547 Votes)
Sol As 392 102 mol of PCl3g added to flask Volume of flask 1 L So Concentration of PCl3g added to flask 392 102 1 00392 M New Initial Concentration of PCl3g
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