Kp = KC*(RT) deltan.
deltan= Change in number of moles during the reaction,
CoCl2-<--->CO +Cl2
deltan=2-1= 1
R= 0.0821 L.atm/mole.K T=527+273=800K
Kp =4.63*10-3*(0.0821*800)1 =0.3
                                          Â
CoCl2Â Â Â Â Â Â Â Â Â Â Â Â Â
COÂ Â Â Â Â Â Â Â Â Â Â Â Â
Cl2
Initial
(atm)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.76Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0
Change                                Â
-x               Â
x              Â
x
equilibrium                       Â
0.76-x           Â
x               Â
x
x= partial pressure
KP= x2/(0.76-x)= 0.3
when solved using excel, x=0.351 atm
Hence at equilbrium Partial pressures : CoCl2= 0.76-0.351=0.409
atm
partial pressure of CO= partial pressure of Cl2= 0.351 atm
