KClO3(s)
+ 3 P4(s) ------- > 3 P4O10(s) + 10 KCl(s)
3 moles of P4 react with KClO3 to form 10 moles of KCl
3*124g of P4 react with KClO3 to form 10*74.5g of KCl
38.56*10-3 g of P4 react with KClO3 to form =
10*74*38.56*10-3/3*124
                                                                            Â
= 28.5344/372Â Â = 0.0767g of KCl
b. KClO3(s) + 3 P4(s) ------- > 3 P4O10(s) + 10 KCl(s)
  1 mole of KClo3 react with P4 to gives 3 moles of
P4O10
0.00625 moles of KClo3 react with P4 to gives = 3*0.00625/1 =
0.01875moles of P4O10
