Initial partial preesure of CO = (
moles of CO / total moles ) x total pressure = ( 1/1+1) x 1 atm =
0.5 atm
    Initial partial preesure of Cl2 = (
moles of Cl2 / total moles ) x total pressure = ( 1/1+1) x 1 atm =
0.5 atm
           Â
CO(g) +Â Â Â Cl2(g)Â Â Â
<=>Â Â Â COCl2(g)
Initial                    Â
0.5 atm       0.5 atm
               Â
0
At
equilibrium         Â
0.5-x         Â
0.5-x                   Â
x
                     Â
Kp = x / (0.5-x) (0.5-x)
                     Â
18 = x / (0.5-x)2
                            Â
18x2 -18x +4.5 = x
                    Â
18x2 -19x +4.5 = 0
On solving,
               Â
x = 0.385 atm
Therefore,
partial pressure of COCl2 after equilibrium is reached = x =
0.385 atm