molality of NaNO3Â Â = 2.81m
2.81m NaNO3 solution means 2.81moles of NaNO3 dissolve in 1Kg
(1000g) of water
no of moles of NaNO3 (n NaNO3) = 2.81 moles
no of moles of H2O (n H2O) = W/G.M.Wt
                                            Â
= 1000/18.02 = 55.55moles
mole fraction of NaNO3Â Â Â = n NaNO3/n NaNO3 + n
H2O
                                        Â
= 2.81/2.81+ 55.55
                                        Â
= 2.81/58.36
                                         Â
= 0.0482
0.0482 >>>>>answer
                               Â
