The person’s mass, m= 68.1 kg, the unknown drag coefficient is,c , with units kg/s, and the local acceleration of gravity is g=9.80 m/s2 . Our model for the person’s velocity vs time gave us alinear differential equation whose analytical solution was thefollowing:
V(t) = g*m/c*[1-exp(-c/m*t)].
Your job is to find “câ€. You need to use the MATLAB “helpâ€documentation to find the nonlinear curve fitting function andsyntax for how to use it. Hint you should use the documentation andexample for “lsqcurvefitâ€.
Include in your program a plot of the experimental velocity data vstime and the calculated velocity vs time. The graph should have atitle, x and y labeled axis, and a legend. It is likely your legendwill not be placed in a good position. Use again the MATLAB “helpâ€documentation to learn how to move it to the southeast cornerinside your plot.
The following table is experimental data regarding ourparachutist. We have a measured velocity versus time after thejump, but before the chute is opened:
Time t (sec)
Velocity, cm/s
0
1
1000
2
1630
3
2300
4
2750
5
3100
6
3560
7
3900
8
4150
9
4290
10
 Â
4500
11
4600
12
4550
13
4600
14
4900
15
5000
