Solution :-
C(s) + S2(g) = CS2(g)
Initial concentration of S2= 3.00 mol / 1.00 L = 3.00 M
Equilibrium concentration of the CS2 = ?
Keq = 3.50
Lets make the Ice table
C(s) +
   S2(g)    -----
>
        CS2(g)
           Â
3.00
MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0
            Â
-x                                Â
+x
          Â
3.00 –x
                       x
Keq = [CS2]/[S2]
3.50 = [x] / [3.00-x]
X= 2.33
Therefore the equilibrium concentration of the CS2(g) = 2.33
M
