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The reaction of the persulfate ion with the iodine ion at room temperature is:           S2O82-     +       2 I-          ↔       2 SO42-       +      ...

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Chemistry

The reaction of the persulfate ion with the iodine ion at roomtemperature is:

         S2O82-    +       2I-         ↔       2SO42-      +       I2      ,    so   rate = k[S2O82-]x[I-]y

The following data was collected at room temperature:

Experiment

[S2O82-](M)

[I-] (M)

Initial Rate (M/s)

1

0.10

0.15

2.61 x 10-5

2

0.20

0.15

5.21 x 10-5

3

0.10

0.30

5.24 x 10-5

Determine the following:

(a) The rate law (including exponents forS2O82- and I-)

(b) The rate constant,k          

Answer & Explanation Solved by verified expert
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