Part A:
          Â
AÂ Â +Â Â B<--->CÂ Â +Â Â
D
Initial:Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
2Â Â Â Â Â Â Â Â
2Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â 0
At equilibrium:Â Â Â Â Â Â Â Â
2-x      Â
2-x     Â
x         x
Kc = ([C][D])/([A][B])
3.4 = x*x / {(2-x)(2-x)}
3.4 = {x / (2-x)}2
(x)/(2-x) = 1.844
x=3.69 - 1.844x
x= 1.3
Concentartion of A at equilibrium = 2-x =2 - 1.3 = 0.7
M
Part B:
          Â
AÂ Â +Â Â B<--->CÂ Â +Â Â
D
Initial:Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
1 Â Â Â Â Â Â
2Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â 0
At equilibrium:Â Â Â Â Â Â Â Â
1-x      Â
2-x     Â
x         x
Kc = ([C][D])/([A][B])
3.4 = x*x / {(1-x)(2-x)}
3.4 = x^2 / (2-3x+x^2)
6.8-10.2x+3.4x^2 =x^2
2.4x^2-10.2x+ 6.8=0
solving above quadratic equation we get, x = 3.4 and 0.83
since x can't be greater than 1 so, x = 0.83
Concentartion of D at equilibrium = x = 0.83
M
