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The Tevatron at Fermilab is a cyclotron capable of producing a maximum energy of 2.0 TeV...

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Physics

The Tevatron at Fermilab is a cyclotron capable of producing amaximum energy of 2.0 TeV (2×1012eV). Its

circumference is 6.4 km. (a) How fast would proton be moving inthe Tevatron? How large of a magnetic

field is required? (b) Repeat part (a) using electronsinstead

of protons.

Answer & Explanation Solved by verified expert
4.5 Ratings (733 Votes)
am mass of proton 167 x 1027 kgv speed of proton KE kinetic energy of proton 2 x 1012 eV 2 x1012 x 16 x 1019 J 32 x 107JUsing the equationKE 05 m v232 x 107 05 167 x    See Answer
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