Given-
The average length of a single nucleotide = 0.34 nm
The number of nucleotides in ONE STRAND of DNA is approximately
= 3.0 x106
Length of one strand of DNA when it is stretched out to its
maximum length = 0.34 nm x 3.0 x106
                                                                                                                                Â
      = 1.02 x 106 nm
1 nm = 10^-12Km
So, 1.02 x 10^6 nm = 1.02 x 10^6 x 10^-12Km = 1.02 x 10^-6Km
The length one strand of DNA when it is stretched out to
its maximum length = 1.02 x 10^-6Km
