P0-P/P0 = x
458.7/463.57Â Â =x
0.989Â Â = x
no of moles of diethyl ether = W/G.M.wt
                                            Â
= 192.8/74.12 = 2.6moles
no of moles of solute ( testosterone) = W/288.4
P0-P/P0 = x ( mole fraction of solute)
458.7/463.57Â Â = 2.6/2.6+z
0.989Â Â =Â Â Â 2.6/2.6+z
0.989(2.6+z) = 2.6
  z  = 0.0289
no of moles of testosterone = W/G.M.Wt
                           Â
0.0289Â Â = W/288.4
                           Â
WÂ Â Â Â Â Â Â Â Â =
0.0289*288.4Â Â = 8.335g >>>> answer