Three dimensions. Three point particles are fixed inplace in an xyz coordinate system. Particle A, atthe origin, has mass mA. Particle B,at xyz coordinates (3.00d, 2.00d,4.00d), has mass 3.00mA, and particleC, at coordinates (–3.00d, 3.00d,–2.00d), has mass 3.00mA. A fourthparticle D, with mass 3.00mA, is to beplaced near the other particles. If distance d = 9.90 m,at what (a) x, (b)y, and (c) z coordinate shouldD be placed so that the net gravitational force onA from B, C, and D is zero?
I need the answer in meters. Also, I already asked and someoneended up getting 0 for part a, -16.5 for part b and 22.9 for partc; none of those are correct. thanks
