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Titration of a 15.0 mL solution of KOH requires 17.0 mL of 0.0250 M H2SO4 solution. What...

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Chemistry

Titration of a 15.0 mL solution of KOH requires 17.0 mL of0.0250 M H2SO4 solution.

What is the molarity of the KOH solution?

M=?

Answer & Explanation Solved by verified expert
4.2 Ratings (641 Votes)

The reaction between sulphuric acid and potassium hydroxide is an example of neutralisation reaction between a base and an acid to give salt and water. The reaction is:

H2SO4   +    KOH                                                    K2SO4    + H2O

For any titration we know that:

                                      M1V1 = M2V2,

Here, M1 = molarity of KOH = ?, V1 = volume of KOH = 15 mL,

          M2 = molarity of sulphuric acid = 0.0250, V2 = volume of sulphuric acid = 17 mL.

by putting the values, we get the value of M1 = 0.0283M.

Therefore, the molarity of KOH is 0.0283M                
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