Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in...

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Treatment of a 0.2496-g sample of impure potassium chloride withan excess of AgNO3 resulted in the formation of 0.2852 g of AgCl.Calculate the percentage of KCl in the sample?
%?

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4.1 Ratings (852 Votes)

KClÂ Â +Â Â AgNO3 ---------------------->Â Â AgCl + KNO3

74.55g Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 143.3 g

??Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.2852 g

KCl needed = 74.55 x 0.2852 / 143.3

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.1484 g

% KClÂ Â = mass of KCl x 100 / sample mass

Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.1484 x 100 / 0.2496

Â Â Â Â Â Â Â Â Â Â Â = 59.44 %

percentage of KCl in the sample = 59.44 %

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Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in...

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80.2K

Verified Solution

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Chemistry

Treatment of a 0.2496-g sample of impure potassium chloride withan excess of AgNO3 resulted in the formation of 0.2852 g of AgCl.Calculate the percentage of KCl in the sample?
%?

Answer & Explanation Solved by verified expert

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Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in...

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80.2K

Verified Solution

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Chemistry

Treatment of a 0.2496-g sample of impure potassium chloride withan excess of AgNO3 resulted in the formation of 0.2852 g of AgCl.Calculate the percentage of KCl in the sample?%?

Answer & Explanation Solved by verified expert

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Treatment of a 0.2496-g sample of impure potassium chloride withan excess of AgNO3 resulted in the formation of 0.2852 g of AgCl.Calculate the percentage of KCl in the sample?
%?