a)Â Â Â Â CO2(g)
+     4H2(g) →   CH4(g)
+Â Â Â 2H2O(g)
      1
mol                                Â
1 mol
     36.6
mol                              Â
? = 36.6 mol
Therefore,
36.6 moles of methane are produced when 36.6 moles of carbon
dioxide gas react with excess hydrogen gas.
b) CO2(g) +Â Â Â Â Â 4H2(g)
→   CH4(g) +   2H2O(g)
                    Â
4
mol                            Â
2 mol
                    Â
?                                 Â
53.6 mol
                     Â
? = 4 mol H2 x (53.6 mol water/ 2 mol water)
                      Â
= 107.2 mol H2
Therefore,
107.2 moles of hydrogen gas would be needed to react with excess
carbon dioxide to produce 53.6 moles of water vapor.