Use a while(true) loop to ask the user the following 2 values“Enter a value x “ “Enter a nonnegative integer n (enter negativeinteger to quit): “
If the user enters a negative int for n, the while loop is brokenvia the brake statement. Otherwise,
in the remaining part of the while loop, use a for loop to computethe partial sum for the Riemann
zeta series for the geometric series, namely 1 + 2ˆ-x + 3ˆ-x + . .. + nˆ-x.
Use the iomanip library in order to print the sum with 50 decimaldigits of precision.
Use the cmath library in order to access the pow function. Forexample pow(3,-x) returns the value
of 3ˆ-x.
Sample output:
Enter a value x = 5
Enter a non-negative integer (enter negative integer to quit):4
1 + 2^-5 + 3^-5 + 4^-5 =1.0363417888374486519609263268648646771907806396484
Enter a value x = -5
Enter a non-negative integer (enter negative integer to quit):4
1 + 2^5 + 3^5 + 4^5 = 1300
Enter a value x = 6
Enter a non-negative integer (enter negative integer to quit):-2
C++.will like if correct,thank you.
