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(Use Excel or R) Wenton Powersports produces dune buggies. They have three assembly lines, “Razor,” “Blazer,” and...

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Basic Math

(Use Excel or R)

Wenton Powersports produces dune buggies. They have threeassembly lines, “Razor,” “Blazer,” and “Tracer,” named after theparticular dune buggy models produced on those lines. Each assemblyline was originally designed using the same target production rate.However, over the years, various changes have been made to thelines. Accordingly, management wishes to determine whether theassembly lines are still operating at the same average hourlyproduction rate. Production data (in dune buggies/hour) for thelast eight hours are as follows.

RazorBlazerTracer
11109
1089
81110
1099
998
9107
13138
1189

a. Specify the competing hypotheses to testwhether there are some differences in the mean production ratesacross the three assembly lines.

  • H0: ?Razor =?Blazer = ?Tracer.HA: Not all population means are equal.

  • H0: ?Razor ??Blazer ? ?Tracer.HA: Not all population means are equal.

  • H0: ?Razor ??Blazer ? ?Tracer.HA: Not all population means are equal.

b-1. Construct an ANOVA table. Assumeproduction rates are normally distributed. (Round "SumSq" to 2 decimal places, "Mean Sq" and "Fvalue" to 3, and "p-value" to 4 decimalplaces.)

b-2. At the 5% significance level, what is theconclusion to the test?

b-3. What about the 10% significance level?

Answer & Explanation Solved by verified expert
4.3 Ratings (652 Votes)

Using Excel: Data > Data Analysis > Anova: Single Factor

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
Razor 8 81 10.125 2.410714
Blazer 8 78 9.75 2.785714
Tracer 8 69 8.625 0.839286
ANOVA
Source of Variation SS df MS F P-value F crit at 0.05
Between Groups 9.75 2 4.875 2.423 0.113017 3.4668
Within Groups 42.25 21 2.012
Total 52 23

a. Null and Alternative hypothesis:

H0: ?Razor = ?Blazer = ?Tracer. HA: Not all population means are equal.

b-1. ANOVA table.

Source of Variation SS df MS F P-value
Between Groups 9.75 2 4.875 2.423 0.1130
Within Groups 42.25 21 2.012
Total 52 23

b-2. As p-value = 0.01130 > 0.05, we fail to reject the null hypothesis.

There is not enough evidence to conclude that not all population means are equal.

b-3. As p-value = 0.01130 > 0.10, we fail to reject the null hypothesis.

There is not enough evidence to conclude that not all population means are equal.
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