BALANCED EQUATION : CH4(g) + 2O2(g) ---> CO2(g) +
2H2O(l)
DH0rxn = (1*DH0f,CO2 +
2*DH0f,H2O)-(1*DH0f,Ch4+2*DH0f,O2)
      = (1*-393.5 +
2*-285.8)-(1*-74.81+2*0)
      = -890.29
kj/mol
no of mol of CH4 burned = w/Mwt
                      Â
= 5/16
                      Â
= 0.3125 mol
1 mol CH4 = 815.48 kj
so that, heat released(q) = n*DHrxn
                        Â
= 0.3125*890.3
                        Â
= 278.22 kj
DHcomb = -278.22 kj
