6)
total frequency= 520
expected frequncy,E = expected proportions*total frequency
=520/5 = 104
answer: 520/5
7)
|
observed frequencey, fo |
expected proportion |
expected frequency,fe |
|
(fo-fe)^2 |
(fO-fE)²/fE |
| 124 |
0.200 |
104.00 |
|
400.00 |
3.846 |
| 74 |
0.200 |
104.00 |
|
900.00 |
8.654 |
| 104 |
0.200 |
104.00 |
|
0.00 |
0.000 |
| 98 |
0.200 |
104.00 |
|
36.00 |
0.346 |
| 120 |
0.200 |
104.00 |
|
256.00 |
2.462 |
answer: ?(fo-fe)^2 = 1592
8)
level of significance, ?= 0.05
Degree of freedom=k-1= 5 -
1 = 4
Critical value = 9.488 [ Excel
function: =chisq.inv.rt(?,df) ]
9)
chi square test statistic,X² = ?(fo-fe)²/fe =
15.308
10)
since, test stat> criitcal value, reject Ho
answer: B.
#Rounds played is not the same at all 5
