putting above data in ascending order:
|
s. no |
x |
|
1 |
0.01 |
|
2 |
0.03 |
|
3 |
0.04 |
|
4 |
0.17 |
|
5 |
0.33 |
|
6 |
0.36 |
|
7 |
0.37 |
|
8 |
0.38 |
|
9 |
0.48 |
|
10 |
0.54 |
|
11 |
0.59 |
|
12 |
0.76 |
|
13 |
0.83 |
|
14 |
0.96 |
|
15 |
0.98 |
|
16 |
0.99 |
|
17 |
1.04 |
|
18 |
1.06 |
|
19 |
1.07 |
|
20 |
1.18 |
|
21 |
1.34 |
|
22 |
1.35 |
|
23 |
1.36 |
|
24 |
1.39 |
|
25 |
1.53 |
|
26 |
1.57 |
|
27 |
1.73 |
|
28 |
1.78 |
|
29 |
1.81 |
|
30 |
1.95 |
|
31 |
1.95 |
|
32 |
1.99 |
|
33 |
2.13 |
|
34 |
2.18 |
|
35 |
2.35 |
|
36 |
2.44 |
|
37 |
2.47 |
|
38 |
2.61 |
|
39 |
2.66 |
|
40 |
2.67 |
|
41 |
2.72 |
|
42 |
2.78 |
|
43 |
2.78 |
|
44 |
2.79 |
|
45 |
2.82 |
|
46 |
2.83 |
|
47 |
2.93 |
|
48 |
2.94 |
|
49 |
2.96 |
|
50 |
2.98 |
|
total |
79.96 |
|
average |
1.5992 |
mean =1.5992
median =middle value =(n+1)/2 th value =(1.53+1.57)/2 =1.55
Q1 =(n+1)/4 th value =(50+1)/4 th vale =0.8125
Q3 =(n+1)*3/4 th value =(50+1)*3/4 th vale =2.6225
hence outer fence =Q3+1.5*(Q3-Q1)=5.3375
as earthquake measuring 7.0 falls outside outer fence ;
therefore it is an outlier.
