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Using the digits 1, 2, 3, 4, 5, 6, 7, 8 we can form 8!...

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Using the digits 1, 2, 3, 4, 5, 6, 7, 8 we can form 8! (= 40320) 8-digitnumbers in which the eight digits are all distinct. For 1 ? k? 40320,let a denote the kth number if these numbers are arranged inincreasing order.12345678, 12345687, 12345768, ..., 87654321;That is, a? = 12345678, a2 = 12345687,..., a40320 = 87654321. Finda2009-a20089

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