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We are given that the perimeter of the rectangle is 88 m Therefore P 88...

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Calculus

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We are given that the perimeter of the rectangle is 88 m Therefore P 88 We substitute this value into the perimeter equation determined in the previous step P 21 2w 88 2 2w We then solve the resulting equation for I 88 2 2w 1 Next we substitute this expression for into the area equation determined in the previous step and expand the result A lw A w Recalling that area must be greater 0 we note that this equation is valid when 0 W

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