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We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adn reacting with 0.75g KOH and 5 mL triethylene...

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Chemistry

We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adnreacting with 0.75g KOH and 5 mL triethylene glycol to producediphenyl acetylene.

What is the theoretical yield?

Answer & Explanation Solved by verified expert
4.1 Ratings (633 Votes)

                    (C6H5)2 C2H2Br2   +    KOH    ---------------->    (C6H5)2 C2

general            340g                                                               178.22g

Given              0.75g                     0.75g                                  0

Here triethylene glycol is a solvent and KOH is excess reagent

340g 1,2-dibromo-1,2-diphenylethane can from 178.22g diphenyl acetylene.

0.75g 1,2-dibromo-1,2-diphenylethane can from 178.22*0.75/340=0.3931g diphenyl acetylene.
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