[H+] = 0.002197 M
pH = -log [H+] = -log (0.002197)
     = 2.66
pH = 2.66
C2H4O2 ---------------> C2H3O2- + H+
0.0250Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â 0
0.0250-x                              Â
x          x
Ka = x^2 / 0.0250 - x
5.37 x 10^-5 = x^2 / 0.0250 - x
x = 1.132 x 10^-3
[H+] = 1.132 x 10^-3 M
pH = -log [H+] = -log(1.132 x 10^-3)
    = 2.95
pH = 2.95
pH change = 2.95 - 2.66 = 0.29
no , pH will not increase one unit. it only increases 0.29
units
