moles of BaCl2 = 207.86 x 0.250 / 1000 = 0.0519
moles of silfuric acid = 150 x 1.750 / 1000 = 0.2625
BaCl2 + H2SO4Â Â ----------------> BaSO4 + 2 HCl
1 mol       1
mol                               Â
0.0519Â Â Â Â Â
0.2625Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
here limiting reagent is BaCl2 so precipitate formed according
to BaCl2.
1 mol of BaCl2 -----------------Â Â 1 mol of BaSO4
0.0519 mol      Â
-----------------Â Â Â ?? BaSO4
moles of BaSO4 = 0.0519
molar mass of BaSO4 = 233.4 g/mol
moles = mass / molar mass
0.0519 = mass / 233.4
mass of precipitate BaSO4 = 12.1 g
