Molarity = moles of
solute
               Â
liter of solution
Step 1: calculation of moles of NH3 in the
solution
     mass of 1 mole of ammonia = 17
g/mol
     so, 13.7g of ammonia =
13.7g
NH3X 1 mole NH3
              Â
17g NH3
                                             Â
= 0.806 mol
step 2: calculation of molarity
        volume of
solution = 1.55 litres
       moles of solute i.e.
NH3 = 0.806 mol
      molarity = 0.806 mol/ 1.55
L
                 Â
= 0.52 mol/L = 0.52 Molar
