Molar mass of PCL3 = 137.33 g/mol
mass of PCL3 = 125.5 g
number of moles of PCL3 = mass/molar mass = 125.5/137.33 = 0.914
mol
Molar mass of CL2 = 71 g/mol
mass of Cl2 = 61.3 g
number of moles of Cl2= mass/molar mass = 61.3/71=0.863 mol
So, Cl2 is limiting reagent.
theoretically,
number of moles of PCl5 produced = 0.863 mol
Molar mass of PCL5 = 208.24 g/mol
Mass of PCl5 produced = number of mole * molar mass = 0.863*208.24
=179.8 g
actual produced = 119.3 g
percentage yield = actual*100/theoretical
                               Â
=119.3*100/179.8
                               Â
=66.4%
Answer: 66.4 %
