Mass of Ca = 40.08 g
Mass of C = 12.01 g
Mass of O : 16.00 x 3 = 48.00
Therefore the total mass of the CaCO3 = 40.08 + 12.01 +
48.00
                                                               Â
= 100.09 g
Now determine the % of each elementof the molecule using the
following formula:
Mass of part / total mass x 100 = Ca
                                                  Â
=40.08 / 100.09 x 100
                                                   Â
= 40.04 % Ca
For Carbon
                                =12.01
/ 100.09 x 100
                                                 Â
= 12.00 % C
For
Oxygen                               Â
= 48.00 / 100.09 x 100
                                                  Â
= 47.96 % O