number of moles of cyclohexylaminoethanesulfonic acid = (1.136 /
207.29)
                                                                                              Â
= 5.48 * 10^-3 moles
pH = pKa + log((salt) / (acid))
The formation of salt depends upon the base because it can
dissociate compltely in ions.
9.24 = 9.39 + log( (x * 22.63) / ((5.48*10^-3) - (x *
22.63)))
number of mole of NaOH = 1.0037 * 10^-4
concentration of NaOH = (1.0037 * 10^-4) * (1000 / 22.63)
                                        Â
= 0.004435 M
