When an object moves along X axis under the action of force F = -kx...
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Physics
When an object moves along X axis under the action of force F = -kx it is said to be performing simple harmonic oscillatory motion about x=0 as mean position (here x is its x coordinate and k is a positive constant). Total energy of oscillation is equal to KA/2 (Assume potential energy to be zero at mean position. Here A is amplitude of oscillation)If energy of oscillation is 18 J, between which points does the block will oscillate?A. between x = 0 and x = 4 mB. between x = -1m and x = 5 mC. between x = -2m and x = 6mD. between x = 1m and x = 3m
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