When heated, ammonium carbonate decomposes as follows: NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature...

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When heated, ammonium carbonate decomposes as follows:NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature theequilibrium constant is K_P = 2.9 x 10^-3.Calculate the total equilibrium pressure at this temperature.

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ans)Â Â Â Â Â as NH4 CO2NH2 is solid ,Kp includes the active mass of NH4CO2NH2.

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Kp =Â Â P²_{NH3 *Â Â Â} P CO₂

Â Â Â Â Â Â Â Â Â Â Â 2.9 * 10^-3 Â Â Â Â = Â Â Â Â ( 2X)² * X

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X³ = 2.9 * 10^-3Â Â /4Â Â = 0.75 * 10^-3

Â Â Â Â Â BY SOLVINGÂ Â Â Â x =Â Â Â Â Â 0.025 atm

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â P_{TOTALÂ Â EQMÂ Â Â Â} = 2 P_{NH3 + P CO2}

_{Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â} = 2* 0.025 + 0.025

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =Â Â Â Â 0.075 atm

Â Â Â Â Â Â Â Â Â Â Â Â thank u

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When heated, ammonium carbonate decomposes as follows: NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature...

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60.1K

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Chemistry

When heated, ammonium carbonate decomposes as follows:NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature theequilibrium constant is K_P = 2.9 x 10^-3.Calculate the total equilibrium pressure at this temperature.

Answer & Explanation Solved by verified expert

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When heated, ammonium carbonate decomposes as follows: NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature...

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Chemistry

When heated, ammonium carbonate decomposes as follows:NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature theequilibrium constant is KP = 2.9 x 10-3.Calculate the total equilibrium pressure at this temperature.

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When heated, ammonium carbonate decomposes as follows:NH4CO2NH2(s) â‡Œ 2NH3(g) + CO2(g). At a certain temperature theequilibrium constant is K_P = 2.9 x 10^-3.Calculate the total equilibrium pressure at this temperature.