When only two treatments are involved, ANOVA and the Student’st test (Chapter 11) result in the same conclusions. Also,for computed test statistics, t2 =F. To demonstrate this relationship, use the followingexample. Fourteen randomly selected students enrolled in a historycourse were divided into two groups, one consisting of 6 studentswho took the course in the normal lecture format. The other groupof 8 students took the course as a distance course format. At theend of the course, each group was examined with a 50-item test. Thefollowing is a list of the number correct for each of the twogroups.
| Traditional Lecture | Distance |
| 45 | 42 |
| 35 | 38 |
| 45 | 42 |
| 36 | 44 |
| 43 | 40 |
| 38 | 46 |
| 42 |
| 44 |
1= Complete the ANOVA table. (Round your SS, MS, andF values to 2 decimal places and p value to 4decimal places.)?
2=a-2. Use a ? = 0.01 level of significance.(Round your answer to 2 decimal places.)
Using the t test from Chapter 11, compute t.(Negative amount should be indicated by a minus sign. Roundyour answer to 3 decimal places.)
There is any difference in the mean test scores.
