m1 = m = 0.5
kg             Â
m2 = m = 0.5 kg
befor collision
v1 =
4.6i                 Â
v2 = 0
after collision
v1'x =
v1'*cos26Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
v2'x = v2'*cos35
v1'y =
v1'*sin26Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
v2'y = v2'*sin35
from momentum conservation
along y
Piy = Pfy
0 = m1*v1'y + m2*v2'y
v1'y = v2'y
v1'*sin26 = v2'*sin35
v1' = v2'*sin35/sin26......(1)
along x axis
Pix = Pfx
m1*v = m1*v1'x + m2*v2'x
v = v1'*cos26 + v2'*cos35.......(2)
using 1 in 2
v = v2'*sin35*cos26/sin26 + v2'*cos35
v*sin26 = v2'*sin35*cos26 + v2'
*cos35*sin26
v*sin26 = v2'*sin(35+26)
v*sin26 = v2'*sin61Â Â Â Â Â Â
<------answer
-------
part(b)
v2' = 4.6*sin26/sin61 = 2.3 m/s
<------answer
part(c)
v1' = v2'*sin35/sin26
v1' = 3 m/s <<------answer
