Answer: (a) 3x+4y=5
Explanation: The equation of a line with slope,
m, and passing through points
(x1, y1) is given by
y-y1=m(x-x1)
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(1)
In the present case, m=-(3/4) and (x1,
y1)=(-1, 2). So, using eqn 1
y-2=-(3/4){x-(-1)}
y-2=-(3/4)(x+1)
4(y-2)=-3(x+1)
4y-8=-3x-3
4y+3x=-3+8
3x+4y=5
This is the required equation in standard form.