acetic acid mass = volume x
density      Â
                Â
= 0.4 ml x 1.05 g/ml
         =
0.42 g
acetic acid moles = mass / Molar mass of acetic
acid
         Â
= 0.42 g / ( 60.05 g/mol)Â Â = 0.007
isoamyl alcohol mass = vol x density
          Â
= 0.4 ml x 0.81 g/ml =0.324 g
isoamyl alcohol moles = mass / molar mass of
it
           Â
= 0.324 g / 88 g/mol
     = 0.0037
acetic acid and isoamyl alcohol react in 1:1
ratio
since relatively isoamyl alcohol is less the liming
reagent is isoamyl alcohol
( densities and molar mass values taken from
web)
