You want to make 750.00 mL of a 0.9550 M aqueous solution ofCr(NO3)2. You have available in lab a bottle of pure Cr(NO3)2 ∙ 6H2O (s), a bottle of 1.672 M Cr(NO3)2 solution and a bottle of0.5005 M Cr(NO3)2.
a) How many grams of the Cr(NO3)2 ∙ 6 H2O (s) would you need touse to prepare the desired solution?
b) How many mL of the 1.672 M Cr(NO3)2 solution would you needto use to prepare the desired solution?
c) Describe how you could use the 0.5005 M Cr(NO3)2 solution toprepare the desired solution.
