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1 - For the insoluble salt lead (ii) phosphate Pb3(PO4)2, the solubility product, Ksp is 3.10x10-44 a- Write...

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Chemistry

1 - For the insoluble salt lead (ii) phosphatePb3(PO4)2, the solubility product,Ksp is 3.10x10-44

a- Write the chemical equation andsolubility product expression forPb3(PO4)2

b- Determine the molar solubility (M) ofPb3(PO4)2

c- Identify wheather the molar solubility ofPb3(PO4)2 will increase ordecrease upon the following changes and explainwhy?

*** The ddition of 0.10 MPb(NO3)2

*** The addition of 0.10 M NaCl

Answer & Explanation Solved by verified expert
3.6 Ratings (538 Votes)

Given that Ksp of Pb3(PO4)2 = 3.10 x 10-44

Pb3(PO4)2 ---------------> 3 Pb2+ + 2 PO43-

                                                3s            2s                         s = molar solubility of Pb3(PO4)2

Ksp = [Pb2+]3 [PO43-]2

  3.10 x 10-44 = (3s)3 (2s)2

3.10 x 10-44 = 108 s5

s = [3.10 x 10-44 / 108]1/5

= 0.78 x 10-9 M

Therefore, molar solubility of Pb3(PO4)2 = 0.78 x 10-9 M

c) Molar solubility (M) of Pb3(PO4)2 after the addition of 0.10 M Pb(NO3)2

          Dut to common ion Pb2+ in Pb(NO3)2 and Pb3(PO4)2 , molar solubility of Pb3(PO4)2 decreases.

Molar solubility (M) of Pb3(PO4)2 after the addition of 0.10 M NaCl

Since there is no common ion, molar solubility of Pb3(PO4)2 is not effected.
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