ksp of Mg(C16H31O2)2 = [Mg2+][C16H31O2]^2
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= S*(2S)^2 = 4S^3
AT 25 CÂ Â KSP = 4S^3 = 3.3*10^-12
      S = solubility =
9.38*10^-5 M
at 50c , ksp = 4s^3 = 4.8*10^-12
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S = solubility = 1.062*10^-4 M
change in solubility = 1.062*10^-4 - 9.38*10^-5 =
1.24*10^-5 M
solubility in g/L = 1.24*10^-5*58.32 = 7.23*10^-4
g/L
in 100 ml solubility , = 7.23*10^-4*100/1000 =
7.23*10^-5 grams
solid magnesium palmitate remains , = 0.015 -
(7.23*10^-5) = 0.01493 g
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