If a solution containing 84.363g of mercury(II) Chlorate is
allowed to react completely with a solution...
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Chemistry
If a solution containing 84.363g of mercury(II) Chlorate isallowed to react completely with a solution containing 14.334g ofsodium sulfide, how many grams of solid precipitate will be formed?How many grams of the reactant in excess will remain after thereaction?
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First the balanced chemical equation HgClO32 Na2SO4 HgSO4 2NaClO3 We see that the mercury chlorate and sodium sulfate react in a 11 mole ratio as the number in front of both formulae is 1 We find the moles of
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