In two consecutive years, 1000 adults in the magical community were asked if they believed that...
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In two consecutive years, 1000 adults in the magical communitywere asked if they believed that Voldemort had returned. The firstyear, 43% believed that he had returned and in the second year, 47%believed that he had returned.
1) Explain why it would be inappropriate to conclude, based onthese percentages alone, that the percentage of adults who believedthat Voldemort had returned increased from the first year to thesecond year.
2) Assume that the conditions have been satisfied. Construct a95% confidence interval for the difference in the proportions ofadults who believed that Voldemort had returned.
3) Based on the confidence interval, can we conclude that theproportion of adults with this belief increased from the first yearto the second year? Explain.
In two consecutive years, 1000 adults in the magical communitywere asked if they believed that Voldemort had returned. The firstyear, 43% believed that he had returned and in the second year, 47%believed that he had returned.
1) Explain why it would be inappropriate to conclude, based onthese percentages alone, that the percentage of adults who believedthat Voldemort had returned increased from the first year to thesecond year.
2) Assume that the conditions have been satisfied. Construct a95% confidence interval for the difference in the proportions ofadults who believed that Voldemort had returned.
3) Based on the confidence interval, can we conclude that theproportion of adults with this belief increased from the first yearto the second year? Explain.
Answer & Explanation Solved by verified expert
a)
it would be inappropriate to conclude, based on these percentages alone, that the percentage of adults who believed that Voldemort had returned increased from the first year to the second year.
as the samples of people were taken from the magical community not from the adults
...............
b)
proportion success of sample 1 , pÌ‚1= Â
x1/n1=Â Â 0.4300
proportion success of sample 1 , p̂ 2=  x2/n2 =
  0.470
level of significance, α =  0.05 Â
     Â
  Â
Z critical value =  Z α/2 =  Â
1.960Â Â
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